J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    Pauling's equation for determining the electronegativity of an element:

    A)  \[{{X}_{A}}-{{X}_{B}}=0.208\sqrt{\Delta }\]

    B)  \[{{X}_{A}}+{{X}_{B}}=0.208\sqrt{\Delta }\]

    C)  \[{{X}_{A}}-{{X}_{B}}={{\Delta }^{2}}\]

    D)  \[{{X}_{A}}-{{X}_{B}}=\sqrt{\Delta }\]

    Correct Answer: A

    Solution :

    Pauling scale is based upon the excess bond energies. Pauling equation form determining the electronegativity of an element is: \[{{X}_{A}}-{{X}_{B}}=0.208\sqrt{\Delta }\] where\[{{X}_{A}},{{X}_{B}}=\]electronegativity values of element A and B \[\Delta =\]polarity of A - B bond.   Note : - \[{{X}_{A}},{{X}_{B}}=\]electronegativity values of elements A and B \[\Delta =\]represents polarity of\[AB\]bond


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