A) \[AlC{{l}_{3}}\]
B) \[C{{l}^{-}}\]
C) \[CO\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: A
Solution :
According to Lewis acid is any species (molecule, radical or ion) that can accept an electron pair to form a co-ordinate covalent bond. Thus acid is an electron deficient species. e.g.,\[B{{F}_{3}},AlC{{l}_{3}},SnC{{l}_{4}},S{{O}_{3}}\]and all cations etc. \[\underset{Lewis\text{ }acid}{\mathop{AlC{{l}_{3}}}}\,+\underset{Lewis\text{ }base}{\mathop{\underset{\bullet \,\bullet }{\overset{\bullet \,\bullet }{\mathop{{}_{\bullet }^{\bullet }Cl\,{{_{\bullet }^{\bullet }}^{-}}}}}\,}}\,\xrightarrow[{}]{{}}\underset{Adduct}{\mathop{C{{l}_{3}}Al\leftarrow \underset{\bullet \,\,\bullet }{\overset{\bullet \,\,\bullet }{\mathop{Cl\,{{_{\bullet }^{\bullet }}^{-}}}}}\,}}\,\] Or\[AlCl_{4}^{-}\]You need to login to perform this action.
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