J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    In the following reaction, X and Y respectively are: \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[{}]{KMn{{O}_{4}}/{{H}^{+}}}\underline{X}\xrightarrow[{{H}_{2}}S{{O}_{4}}/\Delta ]{Y}C{{H}_{2}}C{{O}_{2}}{{C}_{2}}{{H}_{5}}\]

    A)  \[C{{H}_{3}}OH,{{C}_{2}}{{H}_{5}}OH\]

    B)  \[C{{H}_{3}}CHO,C{{H}_{3}}OH\]

    C)  \[C{{H}_{3}}C{{O}_{2}}H,{{C}_{2}}{{H}_{5}}OH\]

    D)  \[{{C}_{2}}{{H}_{4}},C{{H}_{3}}C{{O}_{2}}H\]

    Correct Answer: C

    Solution :

    \[\underset{ethanol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+[O]\xrightarrow[{}]{KMn{{O}_{4}}/{{H}^{+}}}\underset{\begin{smallmatrix}  \,\,\,\,\,\,\,\,\,\,\,\,(X) \\  ethanoic\,acid \end{smallmatrix}}{\mathop{C{{H}_{3}}COOH}}\,\] \[\xrightarrow[\begin{smallmatrix}  {{H}_{2}}S{{O}_{4}}/\Delta  \\  (esterification) \end{smallmatrix}]{{{C}_{2}}{{H}_{5}}OH(Y)}\underset{ethyl\,ethanoate}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,\] Hence, \[X=C{{H}_{3}}COOH\] \[Y={{C}_{2}}{{H}_{5}}OH\]


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