J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    The product formed in the reaction of glycine with benzoyl chloride 4- aq\[NaOH\]:

    A)  \[PhCOC{{H}_{2}}N{{H}_{2}}\] 

    B)  \[PhC{{H}_{2}}N{{H}_{2}}\]

    C)  \[PhCONHC{{H}_{3}}\]

    D) \[PhCONHC{{H}_{2}}C{{O}_{2}}H\]

    Correct Answer: D

    Solution :

                    Glycine reacts with benzoyl chloride in the presence of aq.\[NaOH\]to give benzoylglycine (Hippuric acid). \[\underset{glycine}{\mathop{HOOC.C{{H}_{2}}N{{H}_{2}}}}\,+\underset{benzoly\,chloride}{\mathop{PhCOCl}}\,\xrightarrow[\Delta ]{aq.\,NaOH}\]          \[\underset{\begin{smallmatrix}  benzoyl\text{ }glycine \\  (Hippuric\text{ }acid) \end{smallmatrix}}{\mathop{PhCONHC{{H}_{2}}COOH}}\,+HCl\]


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