A) \[i={{\pi }_{obs}}\times {{\pi }_{cal}}\]
B) \[i={{\pi }_{obs}}+{{\pi }_{cal}}\]
C) \[i={{\pi }_{obs}}-{{\pi }_{cal}}\]
D) \[i=\frac{{{\pi }_{obs}}}{{{\pi }_{cal}}}\]
Correct Answer: D
Solution :
van't Hoff factor\[(i)\]is given by \[i=\frac{observed\text{ }value\text{ }of\text{ }colligative\text{ }property}{normal\text{ }value\text{ }of\text{ }colligative\text{ }property}\] The normal value of colligative property is the theoretically calculated value assuming no association or dissociation. \[\therefore \] \[i=\frac{{{\pi }_{obs}}}{{{\pi }_{cal}}}\]
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