A) \[C{{H}_{3}}Br,\overline{O}H\]
B) \[C{{H}_{3}}Br\]only
C) OH only
D) \[C{{H}_{3}}Br,C{{H}_{3}}OH\]
Correct Answer: A
Solution :
\[C{{H}_{3}}Br+O{{H}^{-}}\xrightarrow{{}}C{{H}_{3}}OH+B{{r}^{-}}\] This reaction proceeds by S^ 2-mechanism Rate \[\propto \] [substrate] [nucleophile] \[Rate\propto [C{{H}_{3}}Br]\text{ }[O{{H}^{-}}]\]You need to login to perform this action.
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