A) Sc
B) Ti
C) Mn
D) Zn
Correct Answer: C
Solution :
\[Mn\]exhibits the maximum number of oxidation states. \[Mn(Z=25):[Ar]\text{ }3{{d}^{5}}4{{s}^{2}}\] It can show +2, +3, +4, +5, +6 and +7 oxidation states.You need to login to perform this action.
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