A) \[{{F}_{p}}={{F}_{e}}\]
B) \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{{{m}_{e}}}{{{m}_{p}}}\]
C) \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{{{m}_{e}}}{{{m}_{p}}}\]
D) \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{m_{e}^{2}}{m_{p}^{2}}\]
Correct Answer: A
Solution :
The force (F) on charge q due to electric field strength E is \[F=qE\] Given, E is uniform, hence \[{{F}_{p}}={{F}_{e}}\]
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