A) 4 hv
B) 3 hv
C) 5 hv
D) \[\frac{5}{2}hv\]
Correct Answer: B
Solution :
From Einstein's photoelectric equation the maximum kinetic energy of photoelectrons emitted from metal surface is given by \[{{E}_{k}}=h{{v}_{1}}-W\] where W is work function of metal. Given,\[W=hv\]and \[{{v}_{1}}=4v\] \[\therefore \] \[{{E}_{k}}=4hv-hv=3hv\]You need to login to perform this action.
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