2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    A battery of emf 2 V and internal resistance 0.1 \[\Omega \] is being charged by a current of 5 A. The potential difference between the terminals of the battery is :

    A)  2.5 V                                    

    B)  1.5 V

    C)  0.5 V                                    

    D)  IV

    Correct Answer: A

    Solution :

                     When r is internal resistance of the battery and i the charging current, then \[V=E+ir\] \[V=2+5\times 0.1=25V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner