A) \[[Pd{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}\]
B) \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]
C) \[N{{a}_{4}}[Fe{{(CN)}_{6}}]\]
D) \[[Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]
Correct Answer: C
Solution :
\[BAN=Z-(ON)+2(CN)\]where ON = oxidation number CN = co-ordination number Z = atomic number \[{{[Fe{{(CN)}_{6}}]}^{4-}}:\] \[EAN=26(-2)+2(6)\] \[=26-2+\text{ }12=36\]You need to login to perform this action.
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