A) 158
B) 31.6
C) 39.5
D) 79
Correct Answer: B
Solution :
\[5{{C}_{2}}O_{4}^{2-}+\underset{+7}{\mathop{2MnO_{4}^{-}}}\,+16{{H}^{+}}\to 10C{{O}_{2}}+2M{{n}^{2+}}\] \[+8{{H}_{2}}O\] Equivalent weight \[=\frac{molecular\text{ }weight}{change\text{ }in\text{ }oxidation\text{ }number}\]You need to login to perform this action.
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