2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    The metal ion in complex A has EAN identical to the atomic number of krypton. A is: (At. no. of\[Cr=24,\text{ }Fe=\text{ }26,\text{ }Pd=46\]):

    A) \[[Pd{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}\]     

    B)  \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]

    C)  \[N{{a}_{4}}[Fe{{(CN)}_{6}}]\] 

    D)  \[[Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]

    Correct Answer: C

    Solution :

                    \[BAN=Z-(ON)+2(CN)\]where ON = oxidation number CN = co-ordination number Z = atomic number \[{{[Fe{{(CN)}_{6}}]}^{4-}}:\] \[EAN=26(-2)+2(6)\] \[=26-2+\text{ }12=36\]


You need to login to perform this action.
You will be redirected in 3 sec spinner