A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
B) \[C{{H}_{3}}-HC(C{{H}_{3}})-H(C)C{{H}_{3}}-C{{H}_{3}}\]
C) \[C{{H}_{3}}-HC(C{{H}_{3}})-C{{H}_{3}}\]
D) \[C{{H}_{3}}CH=CH-C{{H}_{3}}\]
Correct Answer: D
Solution :
Geometrical isomers of\[C{{H}_{3}}CH=CHC{{H}_{3}}\]are
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