A) \[1162\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[1216\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[1362\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[1176\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: B
Solution :
\[\frac{1}{\lambda }={{R}_{H}}\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] For Lyman series, \[{{n}_{1}}=1,{{n}_{2}}=2\] \[\frac{1}{\lambda }=10,9678\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]\] \[=\frac{10,9678\times 3}{4}\] \[\lambda =1216\,{\AA}\]
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