J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    By applying law of mass action, the equilibrium constant,     K     for     the     reaction\[HA+{{H}_{2}}O{{H}_{3}}{{O}^{+}}+\overline{A},\]is given as

    A)  \[K=\frac{[HA][{{H}_{2}}O]}{[{{H}_{3}}{{O}^{+}}][\overline{A}]}\]           

    B)  \[K=\frac{[{{H}_{3}}{{O}^{+}}][\overline{A}]}{[HA][{{H}_{2}}O]}\]

    C)  \[K=\frac{[{{H}_{3}}{{O}^{+}}][{{H}_{2}}O]}{[\overline{A}][HA]}\]           

    D) \[K=\frac{[HA][\overline{A}]}{[{{H}_{2}}O][{{H}_{3}}{{O}^{+}}]}\]

    Correct Answer: B

    Solution :

                    \[HA+{{H}_{2}}O{{H}_{3}}{{O}^{+}}+{{A}^{-}}\]\[K=\frac{[{{H}_{3}}{{O}^{+}}][{{A}^{-}}]}{[HA][{{H}_{2}}O]}\]


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