A) bimolecular reaction
B) Pseudo-unimolecular reaction
C) unimolecular reaction
D) trimolecular reaction
Correct Answer: B
Solution :
\[{{C}_{12}}{{H}_{22}}{{O}_{11}}+\underset{excess}{\mathop{{{H}_{2}}O}}\,\xrightarrow[{}]{dil.\,acid}\]\[\underset{glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,+\underset{fructose}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\]When one of the reactant is present in large excess, the second-order reaction conforms to the first order and is known as pseudo-unimolecular reaction.
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