A) 60 cm
B) 50 cm
C) 40 cm
D) 20 cm
Correct Answer: C
Solution :
In a meter bridge \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{1}{100-l}\] \[\frac{2}{3}=\frac{1}{(100-l)}\] \[\Rightarrow \] \[200-2l=3l\] \[\Rightarrow \] \[5l=200\] \[\therefore \] \[l=40\text{ }cm\]You need to login to perform this action.
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