A) \[-68,000\text{ }cal\]
B) \[-67,800\text{ }cal\]
C) \[-67,050\text{ }cal\]
D) \[+68,500\text{ }cal\]
Correct Answer: A
Solution :
\[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)\] \[\Delta H=\Delta E+\Delta nRT\] \[\Delta H=-67,710-\frac{1}{2}\times 2\times 290\] \[=-68,000cal\]
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