J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    The specific conductance (k) of an electrolyte of 0.1 N concentration is related to equivalent conductance  by the following formula 

    A) \[\Lambda =k\]                

    B)  \[\Lambda =10\,k\]

    C)  \[\Lambda =100\,k\]                    

    D)  \[\Lambda =10,000\,k\]

    Correct Answer: D

    Solution :

                    Equivalent conductance \[(\wedge )\] = specific conductance\[(k)\times \phi \] where,\[\phi =\]volume in cm3 containing 1 g equivalent of electrolyte g equivalent is dissolve in \[=1000\text{ }c{{m}^{3}}\] 1 g equivalent is dissolve in                 \[=\frac{1000}{0.1}c{{m}^{3}}\] \[=10,000\text{ }c{{m}^{3}}\] So,        \[\wedge =10,000\text{ }k\]


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