A) 8R
B) 9R
C) 10R
D) 20R
Correct Answer: B
Solution :
Acceleration due to gravity at a height h from earth?s surface \[g=\frac{GM}{{{(R+h)}^{2}}}\] Since, \[g=\frac{1}{100}\]of g \[\frac{g}{100}=\frac{GM}{{{(R+h)}^{2}}}\] \[\frac{{{(R+h)}^{2}}}{100}=\frac{GM}{g}\] \[\frac{{{(R+h)}^{2}}}{100}={{R}^{2}}\] \[\left[ \because g=\frac{GM}{{{R}^{2}}} \right]\] \[R+h=10R\] \[h=9R\]You need to login to perform this action.
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