A) 4F
B) 3F
C) 2F
D) F
Correct Answer: C
Solution :
\[Y=\frac{F/A}{\Delta l/l}=\frac{F\times l}{A\times \Delta l}\](where V is Youngs modulus of elasticity) Since, V,\[l\]and A remain same. \[F\propto \Delta l\] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{\Delta {{l}_{1}}}{\Delta {{l}_{2}}}\] \[\Rightarrow \] \[\frac{F}{{{F}_{2}}}=\frac{2\times {{10}^{-3}}}{4\times {{10}^{-3}}}\] \[{{F}_{2}}=2F\]You need to login to perform this action.
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