A) \[\frac{M{{B}_{H}}\theta }{1}\]
B) \[\frac{I{{B}_{H}}\theta }{M}\]
C) \[\frac{M\theta }{I{{B}_{H}}}\]
D) \[\frac{I\theta }{M{{B}_{H}}}\]
Correct Answer: A
Solution :
If\[\alpha \]is the angular acceleration produced, then \[I\alpha =M{{B}_{H}}sin\theta \] If\[\theta \]is small, then\[sin\theta \approx \theta \]and hence the angular acceleration is given by \[\alpha =\frac{M{{B}_{H}}\theta }{I}\]
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