A) 3 : 4
B) 3 : 5
C) 2 : 3
D) 4 : 3
Correct Answer: A
Solution :
For wire A Length = 40 cm It is bent into a circle, so \[\therefore \] \[2\pi r=40\] \[r=\frac{40}{2\pi }\] Magnetic induction at centre \[=\frac{{{\mu }_{0}}{{i}_{1}}}{2r}\] For wire B Length = 30 cm It is bent into an arc, so \[\therefore \] \[\theta r=30\] Magnetic induction at centre due to circular arc \[=\frac{{{\mu }_{0}}{{i}_{2}}\theta }{4\pi r}\] Since, \[\frac{{{\mu }_{0}}{{i}_{1}}}{2r}=\frac{{{\mu }_{0}}{{i}_{2}}\theta }{4\pi r}\] \[\Rightarrow \] \[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{\theta }{2\pi }=\frac{30\times 2\pi }{2\pi \times 40}\] \[\Rightarrow \] \[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{3}{4}\]
You need to login to perform this action.
You will be redirected in
3 sec
