A) \[HOCl\]
B) \[HCl\]
C) \[[O]\]
D) \[{{O}_{2}}\]
Correct Answer: C
Solution :
Chlorine reacts slowly with\[{{H}_{2}}O\]to form\[HCl\] and\[HOCl\]. The\[HOCl\]then decomposes into \[HCl\]and\[[O]\]radicals. \[C{{l}_{2}}+{{H}_{2}}OHCl+HOCl\] \[HOCl\xrightarrow{{}}HCl+\underset{\bullet \,\bullet }{\overset{\bullet \,\bullet }{\mathop{{}_{\bullet }^{\bullet }O}}}\,\] These oxygen radicals are very strong oxidizing as well as effective bleaching agent in aqueous solution of\[C{{l}_{2}}\]or hypochlorite salt.
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