A) 0.00428 moles
B) 428 moles
C) 0.428 moles
D) 0.0428 moles
Correct Answer: C
Solution :
Molarity(M) \[=\frac{\frac{weight\text{ }of\text{ }solute}{molecular\text{ }weight\text{ }of\text{ }solute}}{volume\text{ }of\text{ }the\text{ }solution}\times 1000\] \[=\frac{2.5\times 1000}{58.5\times 100}\] \[=0.428\text{ }mol\]You need to login to perform this action.
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