J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    A solid cylinder is rolling down on an inclined plane of angle\[\theta \]. The coefficient of static friction between the plane and cylinder \[{{\mu}_{s}}\]. Then condition for the cylinder not to slip is

    A) \[\tan \theta \ge 3{{\mu }_{s}}\]                             

    B) \[\tan \theta >3{{\mu }_{s}}\]

    C) \[\tan \theta \le 3{{\mu }_{s}}\]                               

    D) \[\tan \theta <3{{\mu }_{s}}\]

    Correct Answer: C

    Solution :

                     For the rolling of a solid cylinder acceleration \[a=\frac{g}{3}\sin \theta \] \[\therefore \]The condition for the cylinder to remain in equilibrium                 \[Ma\le {{\mu }_{s}}R\] \[\Rightarrow \]               \[\frac{1}{3}Mg\sin \theta \le Mg\cos \theta .{{\mu }_{s}}\] Or           \[{{\mu }_{s}}\ge \frac{1}{3}\tan \theta \] Or           \[\tan \theta \le 3{{\mu }_{s}}\]


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