A) one
B) two
C) three
D) four
Correct Answer: A
Solution :
The number of monochloro derivatives of a compound depends upon the type of hydrogen present in the compound. The structure of neo-pentane is \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\] \[\because \]It contains only one type of hydrogens. \[\therefore \]It will give only one monochloro derivative. \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\xrightarrow[{}]{C{{l}_{2}}}{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}Cl\]
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