A)
B) \[C{{H}_{3}}OH\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}\]
Correct Answer: B
Solution :
The compounds having either\[C{{H}_{3}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{C}}\,-\] group or\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-\]group when treated with \[{{I}_{2}}\]and\[NaOH,\]give yellow precipitate of iodoform. \[\therefore \]\[C{{H}_{3}}OH\]does not give iodoform. Note: \[C{{H}_{3}}C{{H}_{2}}OH\]is oxidized to\[C{{H}_{3}}CHO\]and hence, give positive iodoform test.
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