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J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    The latent heat of fusion of ice at\[{{0}^{o}}C\]is 80 cal/g. Entropy change\[(\Delta S)\]accompanying the melting of 1 g of ice at\[{{0}^{o}}C\]would be (units : cal/g/K)

    A)  273                                       

    B)  8.0

    C)  0.0                                        

    D)  0.293

    Correct Answer: D

    Solution :

                    \[\Delta {{S}_{mel}}=\frac{\Delta {{H}_{mel}}}{T}\] \[=\frac{80}{273}\] \[=0.293\text{ }cal/g/K\]


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