A) 6
B) 5
C) 4
D) 2
Correct Answer: B
Solution :
\[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\xrightarrow[{}]{{}}M{{n}^{2+}}+4{{H}_{2}}O\] \[\begin{align} & \underline{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+{{e}^{-}}]5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ & \underline{MnO_{4}^{-}+8{{H}^{+}}+5F{{e}^{2+}}\to M{{n}^{2+}}+5F{{e}^{3+}}+4{{H}_{2}}O} \\ \end{align}\] \[\therefore \]Five electrons gets transferred.
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