A) \[R=\frac{{{u}^{2}}\sin 2\theta }{g}\]
B) \[R=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\]
C) \[R=\frac{{{u}^{2}}}{g}\]
D) \[R={{u}^{2}}\sin \theta \]
Correct Answer: C
Solution :
\[R=\frac{{{u}^{2}}\sin 2\theta }{g},\]At \[\theta ={{45}^{o}},R=\max \] \[\therefore \] \[{{R}_{\max }}=\frac{{{u}^{2}}}{g}\]You need to login to perform this action.
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