A) \[\vec{t}=\vec{p}\times \vec{E}\]
B) \[\vec{t}=\vec{p}.\vec{E}\]
C) \[\vec{t}=2(\vec{p}+\vec{E})\]
D) \[\vec{t}=(\vec{p}+\vec{E})\]
Correct Answer: A
Solution :
Torque\[(\tau )\]acting on the dipole in an uniform external field \[t=either\text{ }force\times perpendicular\text{ }distance\] \[=qE\times 2\text{ }a\text{ }sin\text{ }\theta \] \[=(q\times 2a)\times E\text{ }sin\text{ }\theta \] \[=PE\text{ }sin\,\theta \] or \[\overrightarrow{\tau }=\overrightarrow{P}\times \overrightarrow{E}\]
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