A) 2 m
B) 4 m
C) 5 m
D) 6 m
Correct Answer: B
Solution :
Moment of inertia of circular ring about an axis passing through its centre of mass and perpendicular to its plane \[I=M{{R}^{2}}\] Here, \[I=4kg-{{m}^{2}},\] \[m=1\text{ }kg\] \[\therefore \] \[{{R}^{2}}=\frac{4}{1}=4\] or \[R=2\text{ }m\] Therefore, diameter of ring = 4 m.You need to login to perform this action.
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