A) 3.18
B) 6.36
C) 5.18
D) 1.59
Correct Answer: D
Solution :
\[Y=\frac{Fl}{A\Delta l}\] \[\Rightarrow \] \[\Delta l=\frac{Fl}{AY}\] \[\therefore \] \[\Delta l=\frac{3.18\times {{10}^{8}}\times 1}{2\times {{10}^{11}}}\] \[=1.59\times {{10}^{-3}}m\] \[=1.59\text{ }mm\]You need to login to perform this action.
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