A) v
B) 2v
C) 4v
D) 9v
Correct Answer: C
Solution :
Terminal velocity \[v\propto {{r}^{2}}\] \[\therefore \] \[\frac{v}{v}=\frac{{{(2R)}^{2}}}{{{(R)}^{2}}}\] or \[v=4v\]You need to login to perform this action.
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