A) 2
B) 1
C) 3
D) 4
Correct Answer: B
Solution :
According to molecular orbital theory, \[{{F}_{2}}(18)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] \[\approx \pi 2p_{y}^{2},\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{2}\] \[\therefore \]Bond order in\[{{F}_{2}}=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{10-8}{2}=1\]
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