A) 10
B) 8
C) 6
D) 4
Correct Answer: A
Solution :
Moment of inertia about\[XX,\] \[{{I}_{XX}}=2kg-{{m}^{2}}\] Moment of inertia about the given axis ie, about\[\,YY\], \[{{I}_{\,YY}}={{I}_{XX}}+M{{R}^{2}}\] \[=2+2\times {{(2)}^{2}}\] \[=2+8\] \[=10\,kg-{{m}^{2}}\]You need to login to perform this action.
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