A) - 1 and + 5
B) + 1 and + 4
C) + 5 and + 3
D) - 1 and + 1
Correct Answer: D
Solution :
When chlorine reacts with dilute and cold\[NaOH,\] sodium chloride and sodium hypochloride are formed. \[2NaOH(cold)+C{{l}_{2}}\to NaCl+\underset{\begin{smallmatrix} \,\,\,\,\,\,\,sodium \\ hypochloride \end{smallmatrix}}{\mathop{NaClO}}\,+{{H}_{2}}O\] Let oxidation state of\[Cl\]in\[NaClO\]is\[x\]. \[NaCl\] \[+1+x=0\] \[x=-1\] Let oxidation state of\[Cl\]in\[NaClO\]is\[x\]. \[NaClO\] \[+1+x-2=0\] \[x-1=0\] \[x=+1\] \[\therefore \]Oxidation states of chlorine changes from 0 to- 1 and +1.
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