A) geometrical
B) optical
C) ionisation
D) linkage
Correct Answer: C
Solution :
Since the complexes\[[PtC{{l}_{2}}{{(N{{H}_{3}})}_{4}}]B{{r}_{2}}\]and \[[PtB{{r}_{2}}{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\]have the same molecular formula but on ionisation they give different ions, they exhibit ionisation isomerism. \[[PtC{{l}_{2}}{{(N{{H}_{3}})}_{4}}]B{{r}_{2}}{{[PtC{{l}_{2}}{{(N{{H}_{3}})}_{4}}]}^{2+}}+2B{{r}^{-}}\] \[[PtB{{r}_{2}}{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}{{[PtB{{r}_{2}}{{(N{{H}_{3}})}_{4}}]}^{2+}}+2C{{l}^{-}}\]
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