A) Na
B) \[Cl\]
C) Cr
D) \[Rb\]
Correct Answer: C
Solution :
\[n=4,l=0,m=0\]and\[s=+\frac{1}{2}\]set represents that the last electron enters in a 45 orbital. Among the given options, only Cr is the element, last electron of which enters in a 4s orbital. \[Cr=[Ar]\text{ }3{{d}^{5}},\text{ }4{{s}^{1}}\]You need to login to perform this action.
You will be redirected in
3 sec