A) \[CH\equiv CH>{{H}_{2}}O>ROH>N{{H}_{3}}\]
B) \[{{H}_{2}}O>ROH>CH=CH>N{{H}_{3}}\]
C) \[ROH>N{{H}_{3}}>CH\equiv CH>{{H}_{2}}O\]
D) \[{{H}_{2}}O>ROH>N{{H}_{3}}>CH\equiv CH\]
Correct Answer: B
Solution :
The conjugated bases of the given compounds are as \[O{{H}^{-}},R{{O}^{-}},CH\equiv {{C}^{-}},NH_{2}^{-}\] Higher the stability of conjugate base, higher is the ease to donate a proton and thus, higher is the acidity. Thus, the order of acidic nature is \[{{H}_{2}}O>ROH<CH\equiv CH>N{{H}_{3}}\]
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