question_answer

Formation of methyl tertiary butyl ether by  he reaction of sodium tertiary butoxide and methyl bromide involves

A)  elimination reaction

B)  electrophilic addition reaction

C)  nucleophilic substitution unimolecular reaction

D)  nucleophilic   substitution   bimolecular reaction

Correct Answer: D

Solution :

                The reaction takes place as       \[\xrightarrow[{}]{fast}\underset{methyl\text{ }tertiary\text{ }butyl\text{ }ether}{\mathop{{{(C{{H}_{3}})}_{3}}C-OC{{H}_{3}}}}\,+B{{r}^{-}}\] Since, in this reaction,\[B{{r}^{-}}\]is substituted by the attack of nucleophile\[{{(C{{H}_{3}})}_{3}}C{{O}^{-}},\]it is a nucleophilic substitution reaction. Moreover, the rate of the reaction depends upon the concentration of\[{{(C{{H}_{3}})}_{3}}C{{O}^{-}}\]and\[C{{H}_{3}}Br\]both, so it is a bimolecular reaction.