A) 0.653V
B) 0.889V
C) 0.0653V
D) 2.771V
Correct Answer: A
Solution :
The Nernsts equation, for the half-cell reaction, \[F{{e}^{3+}}+{{e}^{-}}\xrightarrow[{}]{{}}F{{e}^{2+}}\] \[{{E}_{F{{e}^{3+}}/F{{e}^{2+}}}}=E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}-\frac{0.0591}{1}\log \frac{[F{{e}^{2+}}]}{[F{{e}^{3+}}]}\] \[=0.771-0.0591\text{ }\log \frac{2.00}{0.02}\] \[=0.771-0.0591\text{ }\log \text{ }{{10}^{2}}\] \[=0.771-0.0591\times 2\] \[=+0.653V\]You need to login to perform this action.
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