A) 2
B) \[\frac{1}{2}\]
C) \[\sqrt{2}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: D
Solution :
Velocity of effux \[=\sqrt{2gh}\] Here, \[{{h}_{1}}=\frac{H}{2}\] \[\therefore \]\[{{v}_{1}}=\sqrt{2g\frac{H}{2}}\] and \[{{h}_{2}}=H\] \[\therefore \] \[{{v}_{2}}=\sqrt{2gH}\] \[\Rightarrow \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\sqrt{2g\frac{H}{2}}}{\sqrt{2gH}}=\frac{1}{\sqrt{2}}\]You need to login to perform this action.
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