A) \[\frac{1}{3}\]
B) \[\frac{3}{10}\]
C) \[\frac{2}{5}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
Given, \[{{v}_{s}}=30\text{ }m{{s}^{-1}}\] \[{{V}_{o}}=60\text{ }m{{s}^{-1}}\] Apparent frequency\[v=\left[ \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right]\] \[v=v\left[ \frac{330+60}{330-30} \right]\] \[v=v\left[ \frac{390}{300} \right]\]\[\Rightarrow \]\[v=\frac{39}{30}v\] \[\therefore \]Fractional change in frequency \[\frac{\frac{39}{30}v-v}{v}=\frac{9}{30}=\frac{3}{10}\]You need to login to perform this action.
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