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J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    36 g of glucose (molar mass = 180 g/mol) is present in 500 g of water, the molality of the solution is

    A)  0.2                                        

    B)  0.4

    C)  0.8                                        

    D)  1.0

    Correct Answer: B

    Solution :

                    Molality, \[m=\frac{moles\text{ }of\text{ }solute\times 1000}{mass\text{ }of\text{ }solvent\text{ }(in\text{ }g)}\]\[=\frac{36\times 1000}{180\times 500}=0.4\,m\]


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