A) 30.16
B) 2.55
C) 27.5
D) 37.5
Correct Answer: C
Solution :
At STP, \[\because \] Weight of 300 mL of gas = 0.368 g \[\therefore \] Weight of 22400 mL of gas \[=\frac{0.368\times 22400}{300}g/mol\] \[=27.47\text{ }g/mol\] \[\approx 27.5\text{ }g/mol\] \[\because \] Molecular weight of the gas is 27.5. [\[\because \]22400 mL of a gas contains amount equal to molecular weight of the gas.]
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