A) It has an angular shape
B) It decolourises acidified potassium permanganate solution
C) Two \[S-O\] bonds are equal
D) It is a dehydrating agent
Correct Answer: D
Solution :
Sulphur dioxide has angular shape because of the presence of one lone pair of electrons. It reduces the acidified permanganate to\[M{{n}^{2+}},\]thus, decolourises the acidified\[KMn{{O}_{4}}\]solution. \[5S{{O}_{2}}+\underset{coloured}{\mathop{2MnO_{4}^{-}}}\,+2{{H}_{2}}O\xrightarrow[{}]{{}}5SO_{4}^{2-}\] \[+\underset{colourless}{\mathop{2M{{n}^{2+}}}}\,+4{{H}^{+}}\] It is not a dehydrating agent.You need to login to perform this action.
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