A) \[\beta \frac{{{R}_{L}}}{r}and{{\beta }^{2}}\frac{{{R}_{L}}}{r}\]
B) \[\beta \frac{r}{{{R}_{L}}}and{{\beta }^{2}}\frac{{{r}_{{}}}}{{{R}_{L}}}\]
C) \[\beta \frac{{{R}_{L}}}{r}and\beta {{\left( \frac{{{R}_{L}}}{r} \right)}^{2}}\]
D) \[\beta \frac{{{R}_{L}}}{r}and\beta {{\left( \frac{{{R}_{L}}}{r} \right)}^{2}}\]
Correct Answer: A
Solution :
Transistor as CE amplifier Voltage gain\[{{A}_{V}}=\frac{\Delta {{V}_{0}}}{\Delta {{V}_{i}}}={{\beta }_{AC}}\times \operatorname{Re}sis\tan ce\,gain\] \[=\beta \times \frac{{{R}_{L}}}{r}\] Power gain \[=\frac{\Delta {{P}_{0}}}{\Delta {{P}_{i}}}=\beta _{AC}^{2}\times \]Resistance gain \[={{\beta }^{2}}\times \frac{{{R}_{L}}}{r}\]
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